25x^2-1350=0

Solution for 25x^2-1350=0 equation:

25x^2-1350=0

a = 25; b = 0; c = -1350;
Δ = b2-4ac
Δ = 02-4·25·(-1350)
Δ = 135000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{135000}=\sqrt{22500*6}=\sqrt{22500}*\sqrt{6}=150\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150\sqrt{6}}{2*25}=\frac{0-150\sqrt{6}}{50}
=-\frac{150\sqrt{6}}{50}
=-3\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150\sqrt{6}}{2*25}=\frac{0+150\sqrt{6}}{50}
=\frac{150\sqrt{6}}{50}
=3\sqrt{6}
$